Python 斐波那契數(shù)列
斐波那契數(shù)列指的是這樣一個(gè)數(shù)列 0, 1, 1, 2, 3, 5, 8, 13,特別指出:第0項(xiàng)是0,第1項(xiàng)是第一個(gè)1。從第三項(xiàng)開(kāi)始,每一項(xiàng)都等于前兩項(xiàng)之和。
Python 實(shí)現(xiàn)斐波那契數(shù)列代碼如下:
# -*- coding: UTF-8 -*- # Filename : test.py # author by : www.o2fo.com # Python 斐波那契數(shù)列實(shí)現(xiàn) # 獲取用戶輸入數(shù)據(jù) nterms = int(input("你需要幾項(xiàng)?")) # 第一和第二項(xiàng) n1 = 0 n2 = 1 count = 2 # 判斷輸入的值是否合法 if nterms <= 0: print("請(qǐng)輸入一個(gè)正整數(shù)。") elif nterms == 1: print("斐波那契數(shù)列:") print(n1) else: print("斐波那契數(shù)列:") print(n1,",",n2,end=" , ") while count < nterms: nth = n1 + n2 print(nth,end=" , ") # 更新值 n1 = n2 n2 = nth count += 1
執(zhí)行以上代碼輸出結(jié)果為:
你需要幾項(xiàng)? 10 斐波那契數(shù)列: 0 , 1 , 1 , 2 , 3 , 5 , 8 , 13 , 21 , 34 ,
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