scrapy 2.3 嵌套選擇器

選擇方法 (?.xpath()? 或 ?.css()? )返回同一類型選擇器的列表，以便您也可以調(diào)用這些選擇器的選擇方法。下面是一個(gè)例子：

>>> links = response.xpath('//a[contains(@href, "image")]')
>>> links.getall()
['<a href="image1.html">Name: My image 1 <br><img src="image1_thumb.jpg"></a>',
 '<a href="image2.html">Name: My image 2 <br><img src="image2_thumb.jpg"></a>',
 '<a href="image3.html">Name: My image 3 <br><img src="image3_thumb.jpg"></a>',
 '<a href="image4.html">Name: My image 4 <br><img src="image4_thumb.jpg"></a>',
 '<a href="image5.html">Name: My image 5 <br><img src="image5_thumb.jpg"></a>']

>>> for index, link in enumerate(links):
...     href_xpath = link.xpath('@href').get()
...     img_xpath = link.xpath('img/@src').get()
...     print(f'Link number {index} points to url {href_xpath!r} and image {img_xpath!r}')
Link number 0 points to url 'image1.html' and image 'image1_thumb.jpg'
Link number 1 points to url 'image2.html' and image 'image2_thumb.jpg'
Link number 2 points to url 'image3.html' and image 'image3_thumb.jpg'
Link number 3 points to url 'image4.html' and image 'image4_thumb.jpg'
Link number 4 points to url 'image5.html' and image 'image5_thumb.jpg'