當(dāng) ?$haystack
? 并非僅包含類型為 ?$type
? 的變量時報告錯誤,錯誤訊息由 ?$message
? 指定。
?$isNativeType
? 是一個標(biāo)志,用來表明 ?$type
? 是否是原生 PHP 類型。
?assertNotContainsOnly()
? 是與之相反的斷言,并接受相同的參數(shù)。
示例 1.7 assertContainsOnly() 的用法
<?php declare(strict_types=1);
use PHPUnit\Framework\TestCase;
final class ContainsOnlyTest extends TestCase
{
public function testFailure(): void
{
$this->assertContainsOnly('string', ['1', '2', 3]);
}
}
$ phpunit ContainsOnlyTest
PHPUnit latest.0 by Sebastian Bergmann and contributors.
F
Time: 0 seconds, Memory: 5.00Mb
There was 1 failure:
1) ContainsOnlyTest::testFailure
Failed asserting that Array (
0 => '1'
1 => '2'
2 => 3
) contains only values of type "string".
/home/sb/ContainsOnlyTest.php:6
FAILURES!
Tests: 1, Assertions: 1, Failures: 1.
更多建議: