C 練習實例74
題目:連接兩個鏈表。
程序分析:無。
程序源代碼:
// Created by o2fo.com on 15/11/9. // Copyright © 2015年 W3Cschool教程. All rights reserved. // #include <stdlib.h> #include <stdio.h> struct list { int data; struct list *next; }; typedef struct list node; typedef node *link; link delete_node(link pointer,link tmp) { if (tmp==NULL) /*delete first node*/ return pointer->next; else { if(tmp->next->next==NULL)/*delete last node*/ tmp->next=NULL; else /*delete the other node*/ tmp->next=tmp->next->next; return pointer; } } void selection_sort(link pointer,int num) { link tmp,btmp; int i,min; for(i=0;i<num;i++) { tmp=pointer; min=tmp->data; btmp=NULL; while(tmp->next) { if(min>tmp->next->data) { min=tmp->next->data; btmp=tmp; } tmp=tmp->next; } printf("\40: %d\n",min); pointer=delete_node(pointer,btmp); } } link create_list(int array[],int num) { link tmp1,tmp2,pointer; int i; pointer=(link)malloc(sizeof(node)); pointer->data=array[0]; tmp1=pointer; for(i=1;i<num;i++) { tmp2=(link)malloc(sizeof(node)); tmp2->next=NULL; tmp2->data=array[i]; tmp1->next=tmp2; tmp1=tmp1->next; } return pointer; } link concatenate(link pointer1,link pointer2) { link tmp; tmp=pointer1; while(tmp->next) tmp=tmp->next; tmp->next=pointer2; return pointer1; } void main(void) { int arr1[]={3,12,8,9,11}; link ptr; ptr=create_list(arr1,5); selection_sort(ptr,5); }
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